document.write( "Question 257415: a motorist drove a for 2 hours at one speed & then for 3 hours at another speed & one hour at the second speed, he would have covered 2444km. find the two speeds. \n" ); document.write( "
Algebra.Com's Answer #189403 by drk(1908)\"\" \"About 
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This is an RTD problem. Here is a table base on given information:
\n" ); document.write( "motorist . . . . . . . . .rate . . . . . . . . . .time . . . . . . . . . .distance
\n" ); document.write( " . . . . . . . . . . . . . . .. R1 . . . . . . . . . . . .2 . . . . . . . . . .. . 2R1
\n" ); document.write( " . . . . . . . . . . . . . . . .R2 . . . . . . . . . . . .3 . . . . . . . . .. . .3R2
\n" ); document.write( " . . . . . . . . . . . . . . . R2 . . . . . . . . .. . . . 1 . . . . . . . . .. . .1R2
\n" ); document.write( " . . . . . .. . . . . . . . . . .. .. . . . . . . . . . .6 . . . . . .. . . . . . .2444
\n" ); document.write( "We see that
\n" ); document.write( "(i) \"2R1+%2B+4R2++=+2444\"
\n" ); document.write( "or dividing by 2, we get
\n" ); document.write( "(ii) \"R1+%2B+2R2+=+1222\"
\n" ); document.write( "and that the average rate is
\n" ); document.write( "avgR = 2444/6 = 407.33
\n" ); document.write( "This means that
\n" ); document.write( "(iii) \"%28R1%2BR2%29%2F2+=+407.33\"
\n" ); document.write( "or
\n" ); document.write( "(iv) \"R1+%2B+R2+=+814.66\"
\n" ); document.write( "substituting (iv) into (ii) we get
\n" ); document.write( "(v) \"R1+%2B+R2+%2B+R2+=+1222\"
\n" ); document.write( "(vii) \"814.66+%2B+R2+=+1222\"
\n" ); document.write( "solving for R2, we get
\n" ); document.write( "\"R2+=+407.33\"
\n" ); document.write( "This makes R1
\n" ); document.write( "\"R1+=+407.33\"
\n" ); document.write( "--
\n" ); document.write( "The rates appear to be the same.
\n" ); document.write( "
\n" );