document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32387>Question 32387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Yet another brain cramp!  I figured out the answer, but the exact equation to get there escapes me. A man invests $6,000 at a certain rate and $8,000 at a rate that is 1% less than twice the rate at $6,000.  If the total income from both investments is $1,240, find the rate of each investment.  I got 6 % and 11% respectively, but I guessed, checked and revised.  My daughter needs an equation.  Thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18940 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assume that the person invests $6,000 at x% rate.<BR>\n" );
document.write( "$8,000 is then invested at (2x-1)%<BR>\n" );
document.write( "Total interest = x% of 6000 + (2x-1)% of 8000<BR>\n" );
document.write( "=(x/100)(6000) + [(2x-1)/100](8000)<BR>\n" );
document.write( "=60x + 80(2x-1)<BR>\n" );
document.write( "=60x + 160x - 80<BR>\n" );
document.write( "=220x - 80<BR>\n" );
document.write( "Total earnings from the interest = 1240<BR>\n" );
document.write( "=> 220x - 80 = 1240<BR>\n" );
document.write( "=> 220x = 1320<BR>\n" );
document.write( "=> x = 6<BR>\n" );
document.write( "So, $6,000 invested at 6% and $8,000 invested at 11%<BR>\n" );
document.write( " </SPAN>\n" );
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