document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32335>Question 32335</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of a such that \r<BR>\n" );
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document.write( "y^2 -6y + a\r<BR>\n" );
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document.write( "is a perfect square.\r<BR>\n" );
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document.write( "a= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18937 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y^2 -6y + a<BR>\n" );
document.write( "=y^2 - 2*(3y) + a<BR>\n" );
document.write( "=[y^2 - 2*y*3 + 3^2] + (a - 3^2)<BR>\n" );
document.write( "=(y-3)^2 + (a-9)<BR>\n" );
document.write( "For above to be a complete square, the remainder (a-9) has to be zero<BR>\n" );
document.write( "Thus a-9 = 0<BR>\n" );
document.write( "=> a=9 </SPAN>\n" );
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