document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32444>Question 32444</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let C = 125/64. Then find C^ -2/3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18936 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18936\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (125/64)^(-2/3)<BR>\n" );
document.write( "=(64/125)^(2/3)<BR>\n" );
document.write( "=[(4/5)^3](2/3)<BR>\n" );
document.write( "=(4/5)^2<BR>\n" );
document.write( "=16/25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );