document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257413>Question 257413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2 cars leave at a town at the same time & travel in opposite directions .the speed of one car is 12 km/hr moere than the other . thjey are 444 km apart after 3 hours . find the speed of each car .  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189357 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "D1=R3 FOR CAR ONE.<BR>\n" );
document.write( "D2=(R+12)3 FOR CAR TWO.<BR>\n" );
document.write( "D1+D2=444<BR>\n" );
document.write( "444=R*3<BR>\n" );
document.write( "R=444/3<BR>\n" );
document.write( "R=148<BR>\n" );
document.write( "R+(R+12)=148<BR>\n" );
document.write( "2R=148-12<BR>\n" );
document.write( "2R=136<BR>\n" );
document.write( "R=136/2<BR>\n" );
document.write( "R=68 KM/HR. IS THE SPEED OF THE SLOWER CAR.<BR>\n" );
document.write( "68+12=80 KM/HR IS THE SPEED OF THE FASTER CAR.<BR>\n" );
document.write( "PROOF;<BR>\n" );
document.write( "444=68*3+80*3<BR>\n" );
document.write( "444=204+240<BR>\n" );
document.write( "444=444 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );