document.write( "Question 257418: Would someone mind helping me please? \r
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document.write( "The perimeter of a rectangle is 220 inches. the length exceeds the width by 60 inches. find the length and the width \n" );
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Algebra.Com's Answer #189351 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! L=W+60 \n" ); document.write( "2L+2W=220 \n" ); document.write( "2(W+60)+2W=220 \n" ); document.write( "2W+120+2W=220 \n" ); document.write( "4W=220-120 \n" ); document.write( "4W=100 \n" ); document.write( "W=100/4 \n" ); document.write( "W=25 IN. IS THE WIDTH. \n" ); document.write( "L=25+60=85 IN. IS THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "2*85+2*25=220 \n" ); document.write( "170+50=220 \n" ); document.write( "220=220 \n" ); document.write( " |