document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257396>Question 257396</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2K+AR=R-3Y  solve for R </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189326 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2k+ar=r-3y<BR>\n" );
document.write( "2k+3y=r-ar<BR>\n" );
document.write( "2k+3y=r(1-a)<BR>\n" );
document.write( "(2k+3y)/(1-a)=r </SPAN>\n" );
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