document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257391>Question 257391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The heights of 1000 girls at East High School were measured, and the mean was found to be 64 in., with a standard deviation of 2 in. If the heights are approximately normally distributed, about how many of the girls are between 60 and 64 in. tall?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189320 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189320\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The heights of 1000 girls at East High School were measured, and the mean was found to be 64 in., with a standard deviation of 2 in. If the heights are approximately normally distributed, about how many of the girls are between 60 and 64 in. tall?<BR>\n" );
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document.write( "Find the z-scores of 60 and 64.<BR>\n" );
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document.write( "z(60) = (60-64)/2 = -4/2 = -2<BR>\n" );
document.write( "z(64) = (64-64)/2 = 0<BR>\n" );
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document.write( "P(60 < x < 64) = P(-2 < z < 0) = 0.4772...<BR>\n" );
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document.write( "# of girls between 60 and 64 is approx 0.4772*1000 = 477<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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