document.write( "Question 32323: A quantity, its 2/3, its 1/2 ,and its 1/7 , added together, become 9. What is the quantity? \r
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\n" ); document.write( "\n" ); document.write( "A) 42/97 B)197/42 C) 873/42 D)378/55\r
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Algebra.Com's Answer #18925 by venugopalramana(3286)\"\" \"About 
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A quantity, its 2/3, its 1/2 ,and its 1/7 , added together, become 9. What is the quantity?
\n" ); document.write( "ASSUME THE QUANTITY AS X..AND PROCEED AS IF X IS A KNOWN NUMBER LIKE 5 OR 4 OR 10...OR SOME NUMBER.\r
\n" ); document.write( "\n" ); document.write( "A quantity, its 2/3 = X*2/3=2X/3\r
\n" ); document.write( "\n" ); document.write( " its 1/2 = X*/2=X/2 \r
\n" ); document.write( "\n" ); document.write( ",and its 1/7 =X*1/7=X/7
\n" ); document.write( ", added together..WE GET...2X/3 + X/2 + +X/7 = (2*14+ 1*21 +1*6 )X/42=55X/42= 9\r
\n" ); document.write( "\n" ); document.write( "X=42*9/55=378/55..IS THE ANSWER \r
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