document.write( "Question 257192: Solve for x and y in terms of a and b where a ≠ b.\r
\n" ); document.write( "\n" ); document.write( "bx + ay = -2a + b\r
\n" ); document.write( "\n" ); document.write( "b^2x + a^2y = -ab
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Algebra.Com's Answer #189242 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1.\"bx+%2B+ay+=+-2a+%2B+b\"
\n" ); document.write( "2.\"b%5E2%2Ax+%2B+a%5E2%2Ay+=+-ab\"
\n" ); document.write( "Use eq. 1 to solve for x,
\n" ); document.write( "\"bx+%2B+ay+=+b-2a\"
\n" ); document.write( "\"bx=+b-2a-ay\"
\n" ); document.write( "\"b%5E2x=+b%5E2-2ab-aby\"
\n" ); document.write( "Subsitute into eq. 2 and solve for y,
\n" ); document.write( "2.\"b%5E2%2Ax+%2B+a%5E2%2Ay+=+-ab\"
\n" ); document.write( "\"b%5E2-2ab-aby+%2B+a%5E2%2Ay+=+-ab\"
\n" ); document.write( "\"y%28a%5E2-ab%29+=+ab-b%5E2\"
\n" ); document.write( "\"y=+%28ab-b%5E2%29%2F%28a%5E2-ab%29+\"
\n" ); document.write( "\"y=+%28b%2Across%28%28a-b%29%29%29%2F%28a%2Across%28%28a-b%29%29%29+\"
\n" ); document.write( "\"y=+b%2Fa\"
\n" ); document.write( "Then use this to find x,
\n" ); document.write( "\"b%5E2x=+b%5E2-2ab-aby\"
\n" ); document.write( "\"b%5E2x=+b%5E2-2ab-ab%2A%28b%2Fa%29\"
\n" ); document.write( "\"b%5E2x=+b%5E2-2ab-b%5E2%29\"
\n" ); document.write( "\"b%5E2x=-2ab\"
\n" ); document.write( "\"x=-2%28a%2Fb%29\"
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