document.write( "Question 32365This question is from textbook Elementary and Intermediate alegbra
\n" ); document.write( ": I need to find the equation of the parabola that has an ordered pair (1,1), (0,2), and (3,5) as points on the graph. I need to leave the answer in the form y= ax2 + bx +c.\r
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\n" ); document.write( "\n" ); document.write( "Sherri
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Algebra.Com's Answer #18924 by mukhopadhyay(490)\"\" \"About 
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The standard equation of a parabola is y = ax^2+bx+c
\n" ); document.write( "Substitute the ordered pairs in the above equation.
\n" ); document.write( "For (1,1): 1 = a+b+c.........(1)
\n" ); document.write( "For (0,2): 4 = c.............(2)
\n" ); document.write( "For (3,5): 5 = 9a+3b+c......(3)
\n" ); document.write( "From(2), we know c=4
\n" ); document.write( "From (1) and (3):
\n" ); document.write( "a+b = -3......(4)
\n" ); document.write( "9a+3b=1......(5)
\n" ); document.write( "Multiply (4) with -3:
\n" ); document.write( "-3a-3b = 9
\n" ); document.write( "9a+3b = 1
\n" ); document.write( "Sum above two equations:
\n" ); document.write( "6a = 10
\n" ); document.write( "=>a=5/3
\n" ); document.write( "Using equation (4): b=-3 - 5/3=-14/3
\n" ); document.write( "The required equation is y = (5/3)x^2-(14/3)x+4
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