document.write( "Question 257300: (1/27)^2/3\r
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Algebra.Com's Answer #189216 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2F27%29%5E%282%2F3%29=%28root%283%2C1%2F27%29%29%5E2=%281%2F3%29%5E2=1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "So \"%281%2F27%29%5E%282%2F3%29=1%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "\"16%5E%28-3%2F4%29%5E%22%22=%28root%284%2C16%29%29%5E%28-3%29=2%5E%28-3%29=1%2F2%5E3=1%2F8\"\r
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\n" ); document.write( "\n" ); document.write( "So \"16%5E%28-3%2F4%29%5E%22%22=1%2F8\"
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