document.write( "Question 257252: the length of rectangle is increased by 2 cm. if length is increased by 4cm and breadth is decreased by 3cm. the area remains same. find the length & breadth of rectangle \n" ); document.write( "
Algebra.Com's Answer #189192 by CharlesG2(834)\"\" \"About 
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the length of rectangle is increased by 2 cm. if length is increased by 4cm and breadth is decreased by 3cm. the area remains same. find the length & breadth of rectangle\r
\n" ); document.write( "\n" ); document.write( "L Length in cm
\n" ); document.write( "B breadth (another word for width) in cm\r
\n" ); document.write( "\n" ); document.write( "L + 4 cm, B - 3 cm\r
\n" ); document.write( "\n" ); document.write( "A=L*B=(L+4) * (B-3)
\n" ); document.write( "L*B=L*B-3*L+4*B-12
\n" ); document.write( "L*B-L*B+3*L-4*B=-12
\n" ); document.write( "3*L-4*B=-12\r
\n" ); document.write( "\n" ); document.write( "Thinking what you mean by 1st sentence --> The length of rectangle is increased by 2 cm. --> is that L=B+2\r
\n" ); document.write( "\n" ); document.write( "So plugging that in...\r
\n" ); document.write( "\n" ); document.write( "3*(B+2)-4*B=-12
\n" ); document.write( "3*B+6-4*B=-12
\n" ); document.write( "6-B=-12
\n" ); document.write( "-B=-18
\n" ); document.write( "B=18\r
\n" ); document.write( "\n" ); document.write( "so L=20 cm and B=18 cm\r
\n" ); document.write( "\n" ); document.write( "verifying: 20*18=360 cm^2
\n" ); document.write( " (20+4) * (18-3) = 24*15 = 360 cm^2\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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