document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257148>Question 257148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 over x +6 = negative 3\4  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189188 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189188\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let's write this like this:<BR>\n" );
document.write( "3/x +6 = -3\4 Now, let's get rid of the fractions by multiplying both sides by 4x<BR>\n" );
document.write( "12+24x=-3x Now Subtract 12 and add 3x to both sides to give us:<BR>\n" );
document.write( "27x=-12 Divide both sides by 27 will be:<BR>\n" );
document.write( "x=-12/27 or rewritten as  -4/9<BR>\n" );
document.write( "Plug this answer into the original problem to see if it works. <BR>\n" );
document.write( "Make sense?<BR>\n" );
document.write( "RJ <BR>\n" );
document.write( "Check out a new book at:<BR>\n" );
document.write( "www.math-unlock.com  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );