document.write( "Question 257181: How do you solve 3(c-2)/2 = 2(2c+3)/5 ?\r
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Algebra.Com's Answer #189181 by unlockmath(1688)\"\" \"About 
You can put this solution on YOUR website!
Hello,
\n" ); document.write( "First let's get rid of the fractions by multiplying both sides by 10 to give us:
\n" ); document.write( "15(c-2) = 4(2c+3) This can be rewritten as:
\n" ); document.write( "15c-30=8c+12 Add 30 to both sides to be:
\n" ); document.write( "15c=8c+42 Now subtract 8c from both sides to be:
\n" ); document.write( "7c=42 Divide both sides by 7 will result in:
\n" ); document.write( "c=6
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
\n" ); document.write( "Check out a new book at:
\n" ); document.write( "www.math-unlock.com
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