document.write( "Question 257247: a& b do a job in 4-days working together. A alone would takes twice as long to do the job as aB alone takes. How long would each alone require to do a job? \n" ); document.write( "
Algebra.Com's Answer #189164 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x amount of time needed for B to do the job and 2x =amount of time for A \n" ); document.write( "Then B works at the rate of 1/x job per day \n" ); document.write( "And A works at the rate of 1/2x job per day\r \n" ); document.write( "\n" ); document.write( "A & B together work at the rate of 1/4 job per day \n" ); document.write( "So our equation to solve is: \n" ); document.write( "1/x + 1/2x =1/4 multiply each term by 4x \n" ); document.write( "4+2=x \n" ); document.write( "x=6 hours---------------amount of time needed for B to do the job \n" ); document.write( "2x=2*6=12 hours amount of time needed for A to do the job\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "1/6 +1/12=1/4 \n" ); document.write( "2/12 + 1/12=1/4 \n" ); document.write( "3/12=1/4 \n" ); document.write( "1/4=1/4\r \n" ); document.write( "\n" ); document.write( "Hope this helps ------ptaylor \n" ); document.write( " |