document.write( "Question 257247: a& b do a job in 4-days working together. A alone would takes twice as long to do the job as aB alone takes. How long would each alone require to do a job? \n" ); document.write( "
Algebra.Com's Answer #189164 by ptaylor(2198)\"\" \"About 
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Let x amount of time needed for B to do the job and 2x =amount of time for A
\n" ); document.write( "Then B works at the rate of 1/x job per day
\n" ); document.write( "And A works at the rate of 1/2x job per day\r
\n" ); document.write( "\n" ); document.write( "A & B together work at the rate of 1/4 job per day
\n" ); document.write( "So our equation to solve is:
\n" ); document.write( "1/x + 1/2x =1/4 multiply each term by 4x
\n" ); document.write( "4+2=x
\n" ); document.write( "x=6 hours---------------amount of time needed for B to do the job
\n" ); document.write( "2x=2*6=12 hours amount of time needed for A to do the job\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "1/6 +1/12=1/4
\n" ); document.write( "2/12 + 1/12=1/4
\n" ); document.write( "3/12=1/4
\n" ); document.write( "1/4=1/4\r
\n" ); document.write( "\n" ); document.write( "Hope this helps ------ptaylor
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