document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257182>Question 257182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve 2/3 = -2x/3 + 3/4 ?\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189116 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189116\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3 = -2x/3 + 3/4<BR>\n" );
document.write( "8=-8x+9 Eliminate the fraction by multiplying each side by 12 (LCM)<BR>\n" );
document.write( "-8x=-1<BR>\n" );
document.write( "x=1/8<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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