document.write( "Question 32397: for what values of x will (x,y) be a solution of the system of the following equations
\n" ); document.write( "x2+y2 = 25 both intergers are squared
\n" ); document.write( "x+y=1
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Algebra.Com's Answer #18911 by mukhopadhyay(490)\"\" \"About 
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x+y=1 = > y = 1-x;
\n" ); document.write( "x^2+y^2 = 25
\n" ); document.write( "=> x^2 + (1-x)^2 = 25
\n" ); document.write( "=> 2x^2 - 2x + 1 = 25
\n" ); document.write( "=> 2x^2 - 2x - 24 = 0
\n" ); document.write( "=> x^2 - x - 12 = 0
\n" ); document.write( "=> (x-4)(x+3) = 0
\n" ); document.write( "=> x = 4 or x = -3
\n" ); document.write( "If x=4, y = 1-x = -3;
\n" ); document.write( "If x=-3, y = 1-x = 4
\n" ); document.write( "Answer: (x,y) belongs to {(4,-3), (-3,4)}\r
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