document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257158>Question 257158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in how many different ways could 5 people be in line if one has to always be first </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189107 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a certain person is always to be first then the number of possible arrangements is n!=4!=4*3*2=24<BR>\n" );
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