document.write( "Question 257161: I am 61 and my niece is 6. Given this information, how do I write the following alegrabic equation? How old in years will each of us be when I am 3 times as old as my niece? \n" ); document.write( "

Algebra.Com's Answer #189099 by unlockmath(1688) $\"\"$ $\"About$

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Hello,
\n" ); document.write( "Here we go. First set up x as the number of years. So the (61+x) will be you and your niece will be (6+x). Since you'll be 3 times older we can set her age as
\n" ); document.write( "3(6+x). Both of these will then equal each other so the equation is:
\n" ); document.write( "61+x=3(6+x) Rewritten it will be:
\n" ); document.write( "61+x=18+3x Subtract x from both sides gives us:
\n" ); document.write( "61=18+2x Subtract 18 from both sides to be:
\n" ); document.write( "43=2x Now divide both sides by 2
\n" ); document.write( "x=21.5 So now we add this to 6 which will be the niece's age:
\n" ); document.write( "27.5 years old and you are
\n" ); document.write( "82.5 years old
\n" ); document.write( "Make sense?
\n" ); document.write( "RJ
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\n" ); document.write( "www.math-unlock.com \n" ); document.write( "

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