document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257150>Question 257150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What are the measures of the two complementary angles 12q - 9 and 8q + 14? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189098 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What are the measures of the two complementary angles 12q - 9 and 8q + 14?<BR>\n" );
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document.write( "Complementary angles add to 90 degrees<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "12q-9 + 8q+14 = 90<BR>\n" );
document.write( "20q + 5 = 90<BR>\n" );
document.write( "20q = 85<BR>\n" );
document.write( "q = 17/4<BR>\n" );
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document.write( "12q-9 = 12(17/4)-9 = 3*17-9 = 42 degrees<BR>\n" );
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document.write( "8q+14 = 8(17/4)+14 = 2*17+14 = 48 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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