document.write( "Question 257142: A roofer and assistant can repair a roof working together in 6 hours. Working alone the assistant can complete the repair in 14 hours. If the roofer and the assistant work together for 2 hours, and then the assistant is left alone to complete the job, how many more hours should the assistant need to finish the repairs? \n" ); document.write( "
Algebra.Com's Answer #189094 by ankor@dixie-net.com(22740)\"\" \"About 
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A roofer and assistant can repair a roof working together in 6 hours.
\n" ); document.write( " Working alone the assistant can complete the repair in 14 hours.
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\n" ); document.write( "Let x = time required by the roofer working alone (required to do the next part)
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "\"6%2Fx\" + \"6%2F14\" = 1
\n" ); document.write( "Multiply by 14x
\n" ); document.write( "14(6) + 6x = 14x
\n" ); document.write( "84 = 14x - 6x
\n" ); document.write( "84 = 8x
\n" ); document.write( "x = \"84%2F8\"
\n" ); document.write( "x = 10.5 hrs, roofer working alone
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\n" ); document.write( "If the roofer and the assistant work together for 2 hours, and then the assistant is left alone to complete the job, how many more hours should the assistant need to finish the repairs?
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\n" ); document.write( "Let a = additional hrs required by the assistant working alone
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "\"2%2F10.5\" + \"%28a%2B2%29%2F14\" = 1
\n" ); document.write( "Multiply equation by 147 (10.5*14)
\n" ); document.write( "2(14) + 10.5(a+2) = 147
\n" ); document.write( "28 + 10.5a + 21 = 147
\n" ); document.write( "10.5a + 49 = 147
\n" ); document.write( "10.5a = 147 - 49
\n" ); document.write( "10.5a = 98
\n" ); document.write( "a = \"98%2F10.5\"
\n" ); document.write( "a = 9\"1%2F3\" more hrs for assistant to finish the job
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\n" ); document.write( "Prove this with a calc
\n" ); document.write( "2/10.5 + 11.33/14 = 1.00
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