document.write( "Question 32399: how many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50 % solution? \n" ); document.write( "

Algebra.Com's Answer #18909 by mukhopadhyay(490) $\"\"$ $\"About$

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Assume x liters of a 30% alcohol solution is to be mixed with 80 liters of a 80% solution to produce (x+80) liters of a 50% solution.
\n" ); document.write( "=> x*(30%) + 80(80%) = (x+80)(50%)
\n" ); document.write( "=> .3x + 64 = .5x + 40
\n" ); document.write( "=> .2x = 24
\n" ); document.write( "=> x = 120
\n" ); document.write( "Answer: 120 liters \n" ); document.write( "

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