document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257066>Question 257066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of the figure:  (right triangle)\r<BR>\n" );
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document.write( "Perimeter = 23\r<BR>\n" );
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document.write( "left side = 11-x<BR>\n" );
document.write( "right side = 3x-2<BR>\n" );
document.write( "bottom = x+2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189089 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter = a + b + c<BR>\n" );
document.write( "inm our problem, we have<BR>\n" );
document.write( "23 = 11 - x + 3x - 2 + x + 2<BR>\n" );
document.write( "combining like terms, we get<BR>\n" );
document.write( "23 = 3x + 11<BR>\n" );
document.write( "subtract 11 to get<BR>\n" );
document.write( "12 = 3x<BR>\n" );
document.write( "divide by 3 to get<BR>\n" );
document.write( "4 = x<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "left = 11-x = 11- 4 = 7<BR>\n" );
document.write( "right = 3x - 2 = 3*4 - 2 = 12 - 2 = 10<BR>\n" );
document.write( "bottom = x + 2 = 4 + 2 = 6. </SPAN>\n" );
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