document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257070>Question 257070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the perimeter of a rectangle is 68cm. the length is 4 cm than the width identify your two variables. formulate two equations. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189078 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the Lenth =L<BR>\n" );
document.write( "Let the width=B<BR>\n" );
document.write( "Equation 1 ...L=B+4<BR>\n" );
document.write( "Equation 2 ...2(L+B)=68<BR>\n" );
document.write( "*****<BR>\n" );
document.write( "For solving<BR>\n" );
document.write( "substitute L=B+4 in eqn 2<BR>\n" );
document.write( "You get 2(B+4+B)=68<BR>\n" );
document.write( "2(2B+4)=68<BR>\n" );
document.write( "2B+4=68/2<BR>\n" );
document.write( "2B=34-4=30<BR>\n" );
document.write( "B=15<BR>\n" );
document.write( "L=19 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );