document.write( "Question 257039: the sum of two numbers is 50. the first number is 43 less than twice the second number. find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #189065 by College Student(505)\"\" \"About 
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If the first number is 43 less than twice the second number, let:
\n" ); document.write( "2x - 43 = the first number
\n" ); document.write( "x = the second number\r
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\n" ); document.write( "\n" ); document.write( "Since they add up to 50, the equation becomes: \"x%2B2x-43=50\"
\n" ); document.write( "Now solve for x to find the second number, then deduct 43 to find the other number.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=50%2B43\"
\n" ); document.write( "\"3x=93\"
\n" ); document.write( "\"x=93%2F3\"
\n" ); document.write( "\"x=31\"\r
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\n" ); document.write( "\n" ); document.write( "I'll let you find the other number.
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