document.write( "Question 257025: Good evening\r
\n" ); document.write( "\n" ); document.write( "One more question. I think I have the answer yet i'm only 60% sure.\r
\n" ); document.write( "\n" ); document.write( "Find all the zeros of f(x) if f(x) =(x^2-4)^3. Identify any multiple zeros.\r
\n" ); document.write( "\n" ); document.write( "f(x)=0
\n" ); document.write( "(x^2-4)^3=0
\n" ); document.write( "F(4)=(4^2-4)^3=48-12=36-36=0
\n" ); document.write( "F(0)=(0^2-4)^3=0-12=-12+12=0\r
\n" ); document.write( "\n" ); document.write( "Answer: {4, (triple zero)}\r
\n" ); document.write( "\n" ); document.write( "Thank you much
\n" ); document.write( "

Algebra.Com's Answer #189062 by drk(1908)\"\" \"About 
You can put this solution on YOUR website!
The original question was
\n" ); document.write( "f(x) =(x^2-4)^3.
\n" ); document.write( "step 1 - set = 0 to get
\n" ); document.write( "(i) \"f%28x%29+=%28x%5E2-4%29%5E3+=+0\"
\n" ); document.write( "take a cube root to get
\n" ); document.write( "(ii) \"f%28x%29+=%28x%5E2-4%29+=+0\"
\n" ); document.write( "Factoring, we get
\n" ); document.write( "(iii) \"%28x-2%29%28x%2B2%29+=+0\"
\n" ); document.write( "x = 2 and x = -2
\n" ); document.write( "It turns out that
\n" ); document.write( "x = 2 with multiplicity 3
\n" ); document.write( "x = -2 with multiplicity 3
\n" ); document.write( "
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