document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=257077>Question 257077</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive even integers if the product of the second and third is eighty eight more than four times the first.\r<BR>\n" );
document.write( "\n" );
document.write( "So I have (x+2)(x+4)= 4(x)+ 84. Then when I combine like terms I have x^2+2x-76. Is this correct? If so, how does it factor? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189052 by </B><A HREF=/tutors/aboutme.mpl?userid=rajagopalan><B>rajagopalan(174)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rajagopalan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rajagopalan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution  <BR>\n" );
document.write( "you  have (x+2)(x+4)= 4(x)+ 88. <BR>\n" );
document.write( "x^2+6x+8=4x+88 (not eighty four as u assumed)<BR>\n" );
document.write( "x^2+2x-80=0<BR>\n" );
document.write( "x^2-8x+10x-80=0<BR>\n" );
document.write( "x(x-8)+10(x-8)=0<BR>\n" );
document.write( "(x+10)(x-8)=0<BR>\n" );
document.write( "gives x=-10 or 8<BR>\n" );
document.write( "take 8 as positive answer<BR>\n" );
document.write( "0thers are 10 and 12 obviously<BR>\n" );
document.write( "good day<BR>\n" );
document.write( "cheers </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );