document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255180>Question 255180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation 84x + 2y = 64x + 2y for ‘y’ in terms of ‘x’ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189035 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I can  go one better.<BR>\n" );
document.write( "Since there is 2y on both asides we subtract 2y from both sides<BR>\n" );
document.write( "and we get 84x=64x<BR>\n" );
document.write( "The only solution possible is x=0+0y<BR>\n" );
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