document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32413>Question 32413</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the chinese used a way of measuring heighth of a mountin by viewing it from 2 diffrent locations and counculating the angle from where thay were to the top of the mountain.     the frist angle measure was 8.7° and the 2nd was 7.5°.   the two angles were measured from 18,325 feet apart.    how tall is the mountain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18903 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the chinese used a way of measuring heighth of a mountin by viewing it from 2 diffrent locations and counculating the angle from where thay were to the top of the mountain. the frist angle measure was 8.7° and the 2nd was 7.5°. the two angles were measured from 18,325 feet apart. how tall is the mountain?<BR>\n" );
document.write( "LET BT BE THE MOUNTAIN,B BEING THE BOTTOM ON THE GROUND AND  AND T THE TOP.<BR>\n" );
document.write( "LET THE MAN ON THE GROUND VIEWING THE MOUNTAIN BE AT P FIRST ,SEEING AT AN ANGLE OF ELEVATION OF 8.7 DEG..LET HIM MOVE AWAY FROM THE MOUNTAIN FROM P TO Q ON THE GROUND FROM WHERE THE ANGLE OF ELEVATION IS 7.5 DEG.PQ=18325 FT.<BR>\n" );
document.write( "SO IN RIGHT ANGLE TRIANGLE PBT,<BR>\n" );
document.write( "BT=H...HEIGHT OF MOUNTAIN<BR>\n" );
document.write( "TAN(BPT)=TAN(8.7)=BT/PB=H/PB...OR...PB = H/TAN(8.7)=H*COT(8.7)<BR>\n" );
document.write( "IN RIGHT TRIANGLE QBT <BR>\n" );
document.write( "BT=H<BR>\n" );
document.write( "TAN(BQT)=TAN(7.5)=BT/QB=H/QB...OR...QB = H/TAN(7.5)=H*COT(7.5)<BR>\n" );
document.write( "PQ=18325=QB-PB=H*COT(7.5)-H*COT(8.2)=H*{COT(7.5)-COT(8.2)}<BR>\n" );
document.write( "H=18325/{COT(7.5)-COT(8.2)}=<BR>\n" );
document.write( "=27910.4 FT.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );