document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=255973>Question 255973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If $2000 is invested at 10% simple annual interest, how much should be invested at 12% annual simple interest so that the total yearly income from both investments is $5000? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #189004 by </B><A HREF=/tutors/aboutme.mpl?userid=MRperkins><B>MRperkins(300)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MRperkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MRperkins><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=189004\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I=PRT<BR>\n" );
document.write( "Total interest =PRT of the first investment + PRT of the second investment<BR>\n" );
document.write( "Let x=the principle of the second investment<BR>\n" );
document.write( "5000=2000(.10)(1)+x(.12)(1)<BR>\n" );
document.write( "5000=200+.12x<BR>\n" );
document.write( "4800=.12x<BR>\n" );
document.write( "x=$40,000<BR>\n" );
document.write( "Therefore,$40,000 should be invested at 12% interest to make the total yearly income from both investments equal to $5,000. </SPAN>\n" );
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