document.write( "Question 256939: Good afternoon. I need some help with this problem.\r
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document.write( "This is under the title of solving polynomial equations.\r
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document.write( "Solve (x+3)*(x-3)= 40. Identify any double roots.\r
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document.write( "I've tried different methods\r
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document.write( "(x+3)*(x-3)=40 = x^2-9=40 = Answer {7,-7}
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document.write( "(x+3)*(x+3)+40=0
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document.write( "40(x+3)*(x-3)=0
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document.write( "40(x^2-9)=0
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document.write( "5(x-3)*8(x+3)=0
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document.write( "Answer: {3, -3}\r
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document.write( "or \r
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document.write( "(x+3)*(x-3)=40
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document.write( "(7+3)*(-7-3)=40
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document.write( "-70=40
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document.write( "Answer {0,3,-3}\r
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document.write( "I'm really confused so any help is welcome thank you. \n" );
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Algebra.Com's Answer #188991 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Here is the original equation \n" ); document.write( " \n" ); document.write( "step 1 - foil the left side to get \n" ); document.write( " \n" ); document.write( "step 2 - add 9 to get \n" ); document.write( " \n" ); document.write( "step 3 - take a square root to get \n" ); document.write( " \n" ); document.write( "In this case there are no double roots. \n" ); document.write( "-- \n" ); document.write( "to check let x = 7 and we get \n" ); document.write( "(7+3)(7-3) = 40 - - - > 10*4 = 40 = 40 [true] \n" ); document.write( "Now let x = -7 \n" ); document.write( "(-7+3)(-7-3) = 40 - - > (-4)(-10) = 40 = 40 [true] \n" ); document.write( " |