document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256892>Question 256892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6 yd longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 36 yd , find its area. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188939 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188939\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 6 yd longer than its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is 36 yd , find its area\r<BR>\n" );
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document.write( "P perimeter = 2 * (L length + W width)\r<BR>\n" );
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document.write( "L=W+6\r<BR>\n" );
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document.write( "36=2*(W+6+W)<BR>\n" );
document.write( "36=2*(2W+6)<BR>\n" );
document.write( "18=2W+6<BR>\n" );
document.write( "9=W+3<BR>\n" );
document.write( "6=W\r<BR>\n" );
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document.write( "L=W+6<BR>\n" );
document.write( "L=6+6<BR>\n" );
document.write( "L=12\r<BR>\n" );
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document.write( "A=L*W=12*6=72 yards^2<BR>\n" );
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