document.write( "Question 256885: The length of a rectangle is 2 centimeters less than twice its width. The perimeter of the rectangle is 32 cm. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #188932 by CharlesG2(834)\"\" \"About 
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The length of a rectangle is 2 centimeters less than twice its width. The perimeter of the rectangle is 32 cm. What are the dimensions of the rectangle? \r
\n" ); document.write( "\n" ); document.write( "P perimeter = 2 * (L length + W width)
\n" ); document.write( "P = 2 * (2*W -2 + W)
\n" ); document.write( "32 = 2 * (2*W -2 + W)
\n" ); document.write( "16 = 2*W - 2 + W
\n" ); document.write( "16 = 3*W - 2
\n" ); document.write( "18 = 3*W
\n" ); document.write( "6 = W\r
\n" ); document.write( "\n" ); document.write( "L=2*W -2
\n" ); document.write( "L=2*6 -2
\n" ); document.write( "L=12-2
\n" ); document.write( "L=10
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