document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256866>Question 256866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Okay: That question is- The width of a dock is 4m less than the length. The area is 12m squared. \r<BR>\n" );
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document.write( "So i know that I am trying to find the length so that obviously is my x. Then i also know that the width is 4m less than that, but i get so thrown off by the 12 squared that i can't figure out how to set up the problem :/ </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188909 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the area ? length times width.<BR>\n" );
document.write( "You actually don't say what we are looking for. Are we looking for the width, length or both?<BR>\n" );
document.write( "I will use A for area L for length and W for width<BR>\n" );
document.write( "L*W=A<BR>\n" );
document.write( "L*W=12<BR>\n" );
document.write( "W=L-4<BR>\n" );
document.write( "L*(L-4)=12<BR>\n" );
document.write( "L^2-4L-12=0<BR>\n" );
document.write( "(L-6)(L+2)=0<BR>\n" );
document.write( "L=6 meters<BR>\n" );
document.write( "W=L-4=2 meters </SPAN>\n" );
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