document.write( "Question 256861: Log2x+log2(x+2)=log2(x+6) \n" ); document.write( "

Algebra.Com's Answer #188895 by drk(1908) $\"\"$ $\"About$

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Here is the question:
\n" ); document.write( " $\"Log_2%28x%29+%2B+log_2%28x%2B2%29+=+log_2%28x%2B6%29\"$
\n" ); document.write( "since all are base 2 and we see + on the left, we can rewrite as
\n" ); document.write( " $\"log_2%28x%29%28x%2B2%29+=+log_2%28x%2B6%29\"$
\n" ); document.write( "now cross out the log_2 and solve for x as
\n" ); document.write( " $\"x%28x%2B2%29+=+x%2B6\"$
\n" ); document.write( " $\"x%5E2+%2B+2x+-+x+-+6+=+0\"$
\n" ); document.write( " $\"x%5E2+%2B+x+-+6+=+0\"$
\n" ); document.write( " $\"%28x%2B3%29%28x-2%29=0\"$
\n" ); document.write( "So, x = -3 or x = 2.
\n" ); document.write( "If x = -3, then there would be no solution.
\n" ); document.write( "So, x = 2. \n" ); document.write( "

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