document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256851>Question 256851</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three times a number and 7 more than the number is the same as the difference between -11 and twice the number. What is the number?\r<BR>\n" );
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document.write( "I have tried:<BR>\n" );
document.write( "3x+7=-11-2x<BR>\n" );
document.write( "3x+2x=-11-7<BR>\n" );
document.write( "x=-18<BR>\n" );
document.write( "This is wrong according to my instructor. The answer is actually supposed to be -3. How? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188887 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try this!<BR>\n" );
document.write( "3x+(x+7) \"The sum (+) of three times a number (3x) and seven more than the number (x+7)\" is the same as:<BR>\n" );
document.write( "-11-2x \"the difference (-) between -11 and twice the number (2x)<BR>\n" );
document.write( "Putting it al together, we get:<BR>\n" );
document.write( "3x+x+7 = -11-2x Simplify.<BR>\n" );
document.write( "4x+7 = -11-2x Add 2x to both sides.<BR>\n" );
document.write( "6x+7 = -11 Subtract 7 from both sides.<BR>\n" );
document.write( "6x = -18 Finally, divide both sides by 6.<BR>\n" );
document.write( "x = -3 Voila! </SPAN>\n" );
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