document.write( "Question 256815: Determine the value of (x + y + z) if, \r
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document.write( "3x – 2y – 3z = -1
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document.write( "6x + y + 2z = 7
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document.write( "9x + 3y + 4z = 9 \n" );
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Algebra.Com's Answer #188847 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! Here are the equations: \n" ); document.write( "(i) 3x – 2y – 3z = -1 \n" ); document.write( "(ii) \n" ); document.write( "(iii) \n" ); document.write( "step 1 - It may be easier to get rid of the y's first. We want to multiply by easy numbers. Multiply (ii) by 2 and add to (i) to get \n" ); document.write( "(iv) 3x – 2y – 3z = -1 \n" ); document.write( "(v) \n" ); document.write( "and then \n" ); document.write( "(vi) \n" ); document.write( "step 2 - multiply (ii) by -3 and add to (iii) to get \n" ); document.write( "(vii) \n" ); document.write( "(viii) \n" ); document.write( "and then \n" ); document.write( "(ix) \n" ); document.write( "Now, multiply (vi) by 2 and add to (ix) to get \n" ); document.write( "(x) \n" ); document.write( "(xi) \n" ); document.write( "(xii) \n" ); document.write( " \n" ); document.write( "Since x = 2/3, we sub that back into (x) to get \n" ); document.write( " \n" ); document.write( "Now put those both back into (i) to get \n" ); document.write( " \n" ); document.write( "So we finally have {2/3, -3, 3} \n" ); document.write( " |