document.write( "Question 256793: if i add a 20% solution to a 100% solution to get 2 liters of a 75% solution, how much of each do i need? \n" ); document.write( "

Algebra.Com's Answer #188835 by Fombitz(32388) $\"\"$ $\"About$

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Concentration equation
\n" ); document.write( " $\"20A%2B100B=75%282%29=150\"$
\n" ); document.write( "Volume equation
\n" ); document.write( " $\"A%2BB=2\"$
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\n" ); document.write( " $\"A=2-B\"$
\n" ); document.write( " $\"20%282-B%29%2B100B=150\"$
\n" ); document.write( " $\"40-20B%2B100B=150\"$
\n" ); document.write( " $\"80B=110\"$
\n" ); document.write( " $\"B=11%2F8\"$
\n" ); document.write( " $\"A=2-B=16%2F8-11%2F8=5%2F8\"$
\n" ); document.write( "5/8 liter of 20% solution and 11/8 of 100% solution. \n" ); document.write( "

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