document.write( "Question 32403: a man rode a bike for 12 miles and hiked 8. The total time for the trip was 5 hours. If his rate when he was riding a bike was 10mph faster than his rate walking, what was each rate? \n" ); document.write( "
Algebra.Com's Answer #18882 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
 X=WALKING SPEED
\n" ); document.write( "X+10=RIDING SPEED
\n" ); document.write( "Eqaution:
\n" ); document.write( "
\n" ); document.write( "Cross multiply:
\n" ); document.write( "12(x)+8(x+10)=5[(x)(x+10)]
\n" ); document.write( "\"20x%2B80=5%28x%5E2%2B10x%29\"
\n" ); document.write( "\"5x%5E2%2B30x-80=0\"
\n" ); document.write( "\"x%5E2%2B6x-16=0\"
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=1, b=6, c=-16
\n" ); document.write( "\"x+=+%28-6+%2B-+sqrt%28+6%5E2-4%2A1%2A-16+%29%29%2F%282%2A1%29+\"
\n" ); document.write( "Simplfy:
\n" ); document.write( "x=-8 or x=2
\n" ); document.write( "remove negative x=2
\n" ); document.write( "2+10=12
\n" ); document.write( "Hence, his walking speed was 2mph and his bike speed was 12 mph.
\n" ); document.write( "Paul. \n" ); document.write( "
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