document.write( "Question 256726: Kate is three years less than twice as old as her brother Brett. Next year Bretts age will be three forths Kates age. How old are each?
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Algebra.Com's Answer #188793 by ankor@dixie-net.com(22740)\"\" \"About 
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let k = Kate's age now
\n" ); document.write( "let b = Brett's age now
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"Kate is three years less than twice as old as her brother Brett.\"
\n" ); document.write( "k = 2b - 3
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\n" ); document.write( "\"Next year Bretts age will be three fourths Kate's age.\"
\n" ); document.write( "b + 1 = \"3%2F4\"(k + 1)
\n" ); document.write( "Multiply by 4, results;
\n" ); document.write( "4b + 4 = 3(k + 1)
\n" ); document.write( "4b + 4 = 3k + 3
\n" ); document.write( "4b = 3k + 3 - 4
\n" ); document.write( "4b = 3k - 1
\n" ); document.write( "Using the 1st equation, replace k with (2b-3)
\n" ); document.write( "4b = 3(2b-3) - 1
\n" ); document.write( "4b = 6b - 9 - 1
\n" ); document.write( "4b = 6b - 10
\n" ); document.write( "+10 = 6b - 4b
\n" ); document.write( "10 = 2b
\n" ); document.write( "b = 5 yrs is Brett's present age
\n" ); document.write( "then
\n" ); document.write( "k = 2(5) - 3
\n" ); document.write( "k = 7 yrs is Kate's present age
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\n" ); document.write( "Check solutions in the statement:
\n" ); document.write( "\"Next year Bretts age will be three fourths Kate's age.\"
\n" ); document.write( "5 + 1 = \"3%2F4\"(7 + 1)
\n" ); document.write( "6 = \"3%2F4\"*8 \n" ); document.write( "
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