document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256697>Question 256697</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The difference between seven times one number and three times a second number is 25. The sum of twice the first and five times the second is 95. Find the numbers.\r<BR>\n" );
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document.write( "For the first equation, I got 7x-3y=25, and for the second equation I got 2x+5y=95, but I was not sure if I got the first equation right, and I always get stuck on problems like these. Can you please help me? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188777 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188777\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I got 7x-3y=25, and for the second equation I got 2x+5y=95<BR>\n" );
document.write( "You have the equations right.<BR>\n" );
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document.write( "Multiply thru the 1st by 2; Multiply thru the 2nd by 7:<BR>\n" );
document.write( "14x - 6y = 50<BR>\n" );
document.write( "14x + 35y = 7*95<BR>\n" );
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document.write( "Subtract the 1st from the 2nd and solve for \"y\":<BR>\n" );
document.write( "41y = 7*95-50<BR>\n" );
document.write( "y = 15<BR>\n" );
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document.write( "Substitute into 2x+5y=95 to solve for \"x\":<BR>\n" );
document.write( "2x + 5*15 = 95<BR>\n" );
document.write( "2x = 20<BR>\n" );
document.write( "x = 10<BR>\n" );
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document.write( "Solution: (10,15)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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