document.write( "Question 256695: write an equation of the line containing the given point and perpendicular to the given line. Type your answer in the form y=mx+b simplify your answer.
\n" ); document.write( "(9,-9);5x+2y=3 I do not understand how to do any of these problems, please help before I fail.
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Algebra.Com's Answer #188776 by Alan3354(69443)\"\" \"About 
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write an equation of the line containing the given point and perpendicular to the given line. Type your answer in the form y=mx+b simplify your answer.
\n" ); document.write( "(9,-9);5x+2y=3
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\n" ); document.write( "Find the slope of the line:
\n" ); document.write( "5x+2y=3
\n" ); document.write( "Find the slope, m, by putting it in the slope-intercept form y = mx + b.
\n" ); document.write( "That means solve for y.
\n" ); document.write( "5x+2y=3
\n" ); document.write( "2y = -5x + 3
\n" ); document.write( "y = (-5/2)x + 3/2
\n" ); document.write( "The slope is -5/2
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\n" ); document.write( "The slope of lines perpendicular is the negative inverse, +2/5.
\n" ); document.write( "Now the problem is to find the equation of a line thru (9,-9) with a slope of 2/5.
\n" ); document.write( "Use y = mx+b and the point to find b:
\n" ); document.write( "-9 = (2/5)*9 + b
\n" ); document.write( "-9 = (18/5) + b
\n" ); document.write( "b = -9 - 18/5
\n" ); document.write( "b = -63/5
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\n" ); document.write( "y = (2/5)x - 63/5
\n" ); document.write( "That's it, in slope-intercept form.
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