document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256661>Question 256661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with solving this problem. I am confused because it started out with equal first:8x = 9 -5y<BR>\n" );
document.write( "                 8x - 3y = -31\r<BR>\n" );
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document.write( "Do I turn it around to solve like this: 9 - 5y = 8x<BR>\n" );
document.write( "                                        8x -3y = -31\r<BR>\n" );
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document.write( "8x-8x=0 <BR>\n" );
document.write( "5y - 3y = 2y<BR>\n" );
document.write( "80 - 31= 49<BR>\n" );
document.write( "8x = 0<BR>\n" );
document.write( " <BR>\n" );
document.write( "8x - 3y = -31<BR>\n" );
document.write( "I am sorry, I am stuck. Thank you for your help.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188764 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188764\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I would use simple substitituon for this one. You are given <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+9+-5y ALIGN=MIDDLE  ALT=\"8x+=+9+-5y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You are then told<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+8x+-+3y+=+-31 ALIGN=MIDDLE  ALT=\"+8x+-+3y+=+-31\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So take the value for 8x in the first equation and substitute that into the second like this<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+8x+-+3y+=+-31 ALIGN=MIDDLE  ALT=\"+8x+-+3y+=+-31\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%289-5y%29+-+3y+=+-31 ALIGN=MIDDLE  ALT=\"%289-5y%29+-+3y+=+-31\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=9+-+5y+-+3y+=+-31 ALIGN=MIDDLE  ALT=\"9+-+5y+-+3y+=+-31\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-8y+=+-40 ALIGN=MIDDLE  ALT=\"-8y+=+-40\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=5 ALIGN=MIDDLE  ALT=\"y=5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "So, if y=5, you can find x <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+9+-+5y ALIGN=MIDDLE  ALT=\"8x+=+9+-+5y\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+9+-+5%2A5 ALIGN=MIDDLE  ALT=\"8x+=+9+-+5%2A5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+9+-+25 ALIGN=MIDDLE  ALT=\"8x+=+9+-+25\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=8x+=+-16 ALIGN=MIDDLE  ALT=\"8x+=+-16\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+-2 ALIGN=MIDDLE  ALT=\"x+=+-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "So the solution is (-2,5)\r<BR>\n" );
document.write( "\n" );
document.write( "You can also graph the two lines and see that the point they intersect is (-2,5)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%289-8x%29%2F5%2C+%288x%2B31%29%2F3%29 ALIGN=MIDDLE  ALT=\"graph%28400%2C400%2C-10%2C10%2C-10%2C10%2C%289-8x%29%2F5%2C+%288x%2B31%29%2F3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );