document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256543>Question 256543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My daughter is supposed to solve this problem using substitution.  I don't get it.  The problem is:\r<BR>\n" );
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document.write( "    -7x-2y= -13<BR>\n" );
document.write( "     x-2y=11\r<BR>\n" );
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document.write( "Can you help me try to explain this to her? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188729 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188729\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -7x-2y= -13<BR>\n" );
document.write( "x-2y=11 --> x = 2y+11 <BR>\n" );
document.write( "-------------<BR>\n" );
document.write( "Sub for x into the 1st eqn<BR>\n" );
document.write( "-7(2y+11) - 2y = -13<BR>\n" );
document.write( "-14y-77 - 2y = -13<BR>\n" );
document.write( "-16y = 64<BR>\n" );
document.write( "y = -4<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "sub for y into either eqn<BR>\n" );
document.write( "x-2y=11<BR>\n" );
document.write( "x-2(-4) = 11<BR>\n" );
document.write( "x+8 = 11<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( " </SPAN>\n" );
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