document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=256624>Question 256624</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rita's corn field has a perimeter of 18,000 meters. The length of one side is 3 meters less than twice the width. What are the dimensions of the field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #188727 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=188727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the width = x<BR>\n" );
document.write( "Then its length = 2x-3<BR>\n" );
document.write( "Perimeter is 2(x+2x-3) = 18,000<BR>\n" );
document.write( "             2(3x-3) = 18,000<BR>\n" );
document.write( "             6x-6 = 18,000<BR>\n" );
document.write( "             6x = 18006<BR>\n" );
document.write( "              x = 3001<BR>\n" );
document.write( "Therefore the width = 3001 meters<BR>\n" );
document.write( "Length = 2x-3 = 2*3001 - 3 = 6002 -3 = 5999  </SPAN>\n" );
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