document.write( "Question 32356: Would you check my answers on these problems please & correct if need be?
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document.write( "Thank you so much.\r
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document.write( "1.Combine like terms:
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document.write( "3x – 6x2 + 2 – 4x2 + 7x – 1 – 8 + 3x2\r
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document.write( "Answer: 10x – 7x2 - 7\r
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document.write( "2. Solve for x:
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document.write( "7x – 3 = -5x – 18\r
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document.write( "Answer:
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document.write( "7x = -5x – 15
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document.write( "+5x + 5x\r
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document.write( "12x = -15
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document.write( "12 12\r
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document.write( "x = - 1 1/4\r
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document.write( "3. Solve for x:
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document.write( "4(x – 1) + 2 = 3x + 8 – 2x\r
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document.write( "Answer:
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document.write( "4x –4 + 2 = x + 8
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document.write( "-x - x\r
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document.write( "3x –2 = 8
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document.write( " + 2 + 2
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document.write( "3x = 10 x = 3 1/3\r
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document.write( "4. Solve for x:
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document.write( "(x – 4)/2 – 1/5 = (7x + 1)/20\r
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document.write( "Answer:
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document.write( "x/2 –2 –1/5 = 00.5x
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document.write( "x/2 –2.2 = 00.5x
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document.write( "(2) x/2-2.2 = 00.5x
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document.write( "2x/2 –4.4 = 1
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document.write( " + 4.4 + 4.4
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document.write( "2x/2 = 4.5
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document.write( "1x= 4.5
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document.write( "x = 4.5\r
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document.write( "5. Translate to an algebra statement; do not solve:
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document.write( "Three times the sum of a number and seven yields the same result as the twice the same number decreased by four.
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document.write( " Answer: 3a + 7 = 2a –4\r
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document.write( "
Algebra.Com's Answer #18869 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! You can check your answers by substituting the value you get for \n" ); document.write( "the variable into the original equation. \n" ); document.write( "5) 3(a+7)=2(a-4) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |