document.write( "Question 256533: 12x^2-23x=24
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\n" ); document.write( "Please help me set to zero, then solve and do quadratic formula.
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Algebra.Com's Answer #188646 by drk(1908)\"\" \"About 
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We are given:
\n" ); document.write( "\"12x%5E2-23x=24\"
\n" ); document.write( "step 1 - subtract 24 to get
\n" ); document.write( "\"12x%5E2-23x-24=0\"
\n" ); document.write( "step 2 - use the quadratic to get
\n" ); document.write( "\"x+=+%2823+%2B-+sqrt%28+529-4%2A12%2A%28-24%29+%29%29%2F%2824%29+\"
\n" ); document.write( "then
\n" ); document.write( "\"x+=+%2823+%2B-+sqrt%28+1681%29%29%2F%2824%29+\"
\n" ); document.write( "and then
\n" ); document.write( "\"x+=+%2823+%2B-+41%29%2F%2824%29+\"
\n" ); document.write( "So,
\n" ); document.write( "x = 18/24 = -3/4
\n" ); document.write( "or
\n" ); document.write( "x = 64/24 = 8/3
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