document.write( "Question 256475: log 3x=log2+log(x+5) \n" ); document.write( "

Algebra.Com's Answer #188630 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%283x%29=log%282%29%2Blog%28%28x%2B5%29%29\"$
\n" ); document.write( " $\"log%283x%29-log%28%28x%2B5%29%29=log%282%29\"$
\n" ); document.write( " $\"log%283x%2F%28x%2B5%29%29=log%282%29\"$
\n" ); document.write( " $\"3x%2F%28x%2B5%29=2\"$
\n" ); document.write( " $\"3x=2%28x%2B5%29\"$
\n" ); document.write( " $\"3x=2x%2B10\"$
\n" ); document.write( " $\"x=10\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );