document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=32339>Question 32339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of a number and 4 times its reciprocal is 25 over 6...\r<BR>\n" );
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document.write( "equation is: X+4(1/X)+25/6...   but how do I solve this?\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18861 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18861\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X+4/X=25/6 OR (X~2+4)/X=25/6 OR 6X~2+24=25X OR 6X~2-25X=24=0 OR\r<BR>\n" );
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document.write( "(3X-8)(2X-3)=0 OR 3X-8=0 OR 3X=8 OR X=8/3 AND 2X-3=0 OR 2X=3 OR X=2/3\r<BR>\n" );
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document.write( "PROOF 8/3+4/(8/3)=25/6 OR 8/3+4*(3/8)=25/6 OR 8/3+12/8=25/6 OR<BR>\n" );
document.write( "64/24+36/24=25/6 OR 100/24=25/6 OR 25/6=25/6 </SPAN>\n" );
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